x^2-10x+53=0

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Solution for x^2-10x+53=0 equation:


Simplifying
x2 + -10x + 53 = 0

Reorder the terms:
53 + -10x + x2 = 0

Solving
53 + -10x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-53' to each side of the equation.
53 + -10x + -53 + x2 = 0 + -53

Reorder the terms:
53 + -53 + -10x + x2 = 0 + -53

Combine like terms: 53 + -53 = 0
0 + -10x + x2 = 0 + -53
-10x + x2 = 0 + -53

Combine like terms: 0 + -53 = -53
-10x + x2 = -53

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = -53 + 25

Reorder the terms:
25 + -10x + x2 = -53 + 25

Combine like terms: -53 + 25 = -28
25 + -10x + x2 = -28

Factor a perfect square on the left side:
(x + -5)(x + -5) = -28

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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